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554101213102061 is a prime number
BaseRepresentation
bin111110111111100111011110…
…1111110011111111111101101
32200122220120002020201220221012
41331333032331332133333231
51040111343241023231221
65242250325545115005
7224466330414645302
oct17577167576377755
92618816066656835
10554101213102061
11150610006453109
125219063b188a65
131aa2469bb22aa1
149ab88db1a50a9
15440d69deca65b
hex1f7f3bdf9ffed

554101213102061 has 2 divisors, whose sum is σ = 554101213102062. Its totient is φ = 554101213102060.

The previous prime is 554101213102027. The next prime is 554101213102067. The reversal of 554101213102061 is 160201312101455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 553087152018025 + 1014061084036 = 23517805^2 + 1007006^2 .

It is a cyclic number.

It is not a de Polignac number, because 554101213102061 - 238 = 553826335195117 is a prime.

It is a super-2 number, since 2×5541012131020612 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554101213102067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277050606551030 + 277050606551031.

It is an arithmetic number, because the mean of its divisors is an integer number (277050606551031).

Almost surely, 2554101213102061 is an apocalyptic number.

It is an amenable number.

554101213102061 is a deficient number, since it is larger than the sum of its proper divisors (1).

554101213102061 is an equidigital number, since it uses as much as digits as its factorization.

554101213102061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 32.

The spelling of 554101213102061 in words is "five hundred fifty-four trillion, one hundred one billion, two hundred thirteen million, one hundred two thousand, sixty-one".