Base | Representation |
---|---|
bin | 111110111111101101000101… |
… | …1000001010011111100100010 |
3 | 2200122221201010122022021211220 |
4 | 1331333122023001103330202 |
5 | 1040112042410213244020 |
6 | 5242300035405515510 |
7 | 224500234502163333 |
oct | 17577321301237442 |
9 | 2618851118267756 |
10 | 554113243103010 |
11 | 15061511a035958 |
12 | 52192a37b72b96 |
13 | 1aa2586825cb46 |
14 | 9ab931cb9228a |
15 | 440db551c5240 |
hex | 1f7f68b053f22 |
554113243103010 has 64 divisors (see below), whose sum is σ = 1350960340181760. Its totient is φ = 145438313875200.
The previous prime is 554113243102997. The next prime is 554113243103027. The reversal of 554113243103010 is 10301342311455.
It is a super-3 number, since 3×5541132431030103 (a number of 45 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 560610837 + ... + 561598376.
It is an arithmetic number, because the mean of its divisors is an integer number (21108755315340).
Almost surely, 2554113243103010 is an apocalyptic number.
554113243103010 is an abundant number, since it is smaller than the sum of its proper divisors (796847097078750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
554113243103010 is a wasteful number, since it uses less digits than its factorization.
554113243103010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1122209483.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 554113243103010 its reverse (10301342311455), we get a palindrome (564414585414465).
The spelling of 554113243103010 in words is "five hundred fifty-four trillion, one hundred thirteen billion, two hundred forty-three million, one hundred three thousand, ten".
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