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554122052153141 is a prime number
BaseRepresentation
bin111110111111110001001100…
…0000101001010111100110101
32200122222112212120002101212212
41331333202120011022330311
51040112213430322400031
65242304053450223205
7224500666005652253
oct17577423005127465
92618875776071785
10554122052153141
1115061892a56567a
1252194696124b05
131aa266402a4244
149ab9916a9d5d3
15440debd73412b
hex1f7f89814af35

554122052153141 has 2 divisors, whose sum is σ = 554122052153142. Its totient is φ = 554122052153140.

The previous prime is 554122052153123. The next prime is 554122052153143. The reversal of 554122052153141 is 141351250221455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 529733724243025 + 24388327910116 = 23015945^2 + 4938454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-554122052153141 is a prime.

Together with 554122052153143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554122052153143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277061026076570 + 277061026076571.

It is an arithmetic number, because the mean of its divisors is an integer number (277061026076571).

Almost surely, 2554122052153141 is an apocalyptic number.

It is an amenable number.

554122052153141 is a deficient number, since it is larger than the sum of its proper divisors (1).

554122052153141 is an equidigital number, since it uses as much as digits as its factorization.

554122052153141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240000, while the sum is 41.

The spelling of 554122052153141 in words is "five hundred fifty-four trillion, one hundred twenty-two billion, fifty-two million, one hundred fifty-three thousand, one hundred forty-one".