Base | Representation |
---|---|
bin | 110011100111111101… |
… | …000110100100010101 |
3 | 12022002002111210102221 |
4 | 303213331012210111 |
5 | 1402010334142013 |
6 | 41244214102341 |
7 | 4001431050454 |
oct | 634775064425 |
9 | 168062453387 |
10 | 55431162133 |
11 | 2156549a5a6 |
12 | a8ab94a9b1 |
13 | 52c5030b29 |
14 | 297bb88b9b |
15 | 16965b808d |
hex | ce7f46915 |
55431162133 has 2 divisors, whose sum is σ = 55431162134. Its totient is φ = 55431162132.
The previous prime is 55431162119. The next prime is 55431162161. The reversal of 55431162133 is 33126113455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55421163889 + 9998244 = 235417^2 + 3162^2 .
It is a cyclic number.
It is not a de Polignac number, because 55431162133 - 213 = 55431153941 is a prime.
It is a super-2 number, since 2×554311621332 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55431162433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27715581066 + 27715581067.
It is an arithmetic number, because the mean of its divisors is an integer number (27715581067).
Almost surely, 255431162133 is an apocalyptic number.
It is an amenable number.
55431162133 is a deficient number, since it is larger than the sum of its proper divisors (1).
55431162133 is an equidigital number, since it uses as much as digits as its factorization.
55431162133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 32400, while the sum is 34.
Adding to 55431162133 its reverse (33126113455), we get a palindrome (88557275588).
The spelling of 55431162133 in words is "fifty-five billion, four hundred thirty-one million, one hundred sixty-two thousand, one hundred thirty-three".
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