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55434220202531 is a prime number
BaseRepresentation
bin11001001101010110010010…
…00000001110101000100011
321021021110102010012011110102
430212223021000032220203
524231213240332440111
6313522043523453015
714450663440125512
oct1446531100165043
9237243363164412
1055434220202531
1116732580156665
12627363422716b
1324c156991aa11
14d9905dc72679
15661e8812413b
hex326ac900ea23

55434220202531 has 2 divisors, whose sum is σ = 55434220202532. Its totient is φ = 55434220202530.

The previous prime is 55434220202497. The next prime is 55434220202533. The reversal of 55434220202531 is 13520202243455.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55434220202531 is a prime.

It is a super-2 number, since 2×554342202025312 (a number of 28 digits) contains 22 as substring.

Together with 55434220202533, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (55434220202533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27717110101265 + 27717110101266.

It is an arithmetic number, because the mean of its divisors is an integer number (27717110101266).

Almost surely, 255434220202531 is an apocalyptic number.

55434220202531 is a deficient number, since it is larger than the sum of its proper divisors (1).

55434220202531 is an equidigital number, since it uses as much as digits as its factorization.

55434220202531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 38.

Adding to 55434220202531 its reverse (13520202243455), we get a palindrome (68954422445986).

The spelling of 55434220202531 in words is "fifty-five trillion, four hundred thirty-four billion, two hundred twenty million, two hundred two thousand, five hundred thirty-one".