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5544306067477 is a prime number
BaseRepresentation
bin101000010101110001001…
…1001001100100000010101
3201122000211020000021020211
41100223202121030200111
51211314214323124402
615443004040325421
71111364033666062
oct120534231144025
921560736007224
105544306067477
111848366265251
12756634a73871
13312a974296c8
141524badddc69
1599347dbd4d7
hex50ae264c815

5544306067477 has 2 divisors, whose sum is σ = 5544306067478. Its totient is φ = 5544306067476.

The previous prime is 5544306067457. The next prime is 5544306067483. The reversal of 5544306067477 is 7747606034455.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4127422939236 + 1416883128241 = 2031606^2 + 1190329^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5544306067477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5544306067457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2772153033738 + 2772153033739.

It is an arithmetic number, because the mean of its divisors is an integer number (2772153033739).

Almost surely, 25544306067477 is an apocalyptic number.

It is an amenable number.

5544306067477 is a deficient number, since it is larger than the sum of its proper divisors (1).

5544306067477 is an equidigital number, since it uses as much as digits as its factorization.

5544306067477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 59270400, while the sum is 58.

The spelling of 5544306067477 in words is "five trillion, five hundred forty-four billion, three hundred six million, sixty-seven thousand, four hundred seventy-seven".