Base | Representation |
---|---|
bin | 11001001101100110111001… |
… | …01111111001011001010111 |
3 | 21021022022102211222221221002 |
4 | 30212303130233321121113 |
5 | 24231340023144301101 |
6 | 313530121052013515 |
7 | 14451430505062151 |
oct | 1446633457713127 |
9 | 237268384887832 |
10 | 55443141400151 |
11 | 16736338a1445a |
12 | 6275303a6129b |
13 | 24c235bc69a8b |
14 | d99668a13ad1 |
15 | 66230b436d6b |
hex | 326cdcbf9657 |
55443141400151 has 2 divisors, whose sum is σ = 55443141400152. Its totient is φ = 55443141400150.
The previous prime is 55443141400123. The next prime is 55443141400159. The reversal of 55443141400151 is 15100414134455.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55443141400151 - 210 = 55443141399127 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55443141400159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27721570700075 + 27721570700076.
It is an arithmetic number, because the mean of its divisors is an integer number (27721570700076).
Almost surely, 255443141400151 is an apocalyptic number.
55443141400151 is a deficient number, since it is larger than the sum of its proper divisors (1).
55443141400151 is an equidigital number, since it uses as much as digits as its factorization.
55443141400151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96000, while the sum is 38.
The spelling of 55443141400151 in words is "fifty-five trillion, four hundred forty-three billion, one hundred forty-one million, four hundred thousand, one hundred fifty-one".
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