Base | Representation |
---|---|
bin | 11001001111011011001001… |
… | …00101110011111110001101 |
3 | 21021112021112012210022112121 |
4 | 30213231210211303332031 |
5 | 24233400331300000023 |
6 | 314014521520532541 |
7 | 14456100162321661 |
oct | 1447554445637615 |
9 | 237467465708477 |
10 | 55505550000013 |
11 | 1675a853a48213 |
12 | 6285420481151 |
13 | 24c81c6704089 |
14 | d9c6a93248a1 |
15 | 663c6035dd5d |
hex | 327b64973f8d |
55505550000013 has 2 divisors, whose sum is σ = 55505550000014. Its totient is φ = 55505550000012.
The previous prime is 55505550000001. The next prime is 55505550000023. The reversal of 55505550000013 is 31000005550555.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35051159841604 + 20454390158409 = 5920402^2 + 4522653^2 .
It is a cyclic number.
It is not a de Polignac number, because 55505550000013 - 213 = 55505549991821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55505550000023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27752775000006 + 27752775000007.
It is an arithmetic number, because the mean of its divisors is an integer number (27752775000007).
Almost surely, 255505550000013 is an apocalyptic number.
It is an amenable number.
55505550000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
55505550000013 is an equidigital number, since it uses as much as digits as its factorization.
55505550000013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46875, while the sum is 34.
Adding to 55505550000013 its reverse (31000005550555), we get a palindrome (86505555550568).
The spelling of 55505550000013 in words is "fifty-five trillion, five hundred five billion, five hundred fifty million, thirteen", and thus it is an aban number.
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