Base | Representation |
---|---|
bin | 11001010000011101011011… |
… | …01101100011101000011101 |
3 | 21021122200101022002002120122 |
4 | 30220032231231203220131 |
5 | 24234441221421132443 |
6 | 314043125035124325 |
7 | 14461500065531321 |
oct | 1450165555435035 |
9 | 237580338062518 |
10 | 55541136505373 |
11 | 1677395566a422 |
12 | 62902b22a36a5 |
13 | 24cb6782aa23c |
14 | da02c36a3981 |
15 | 664b44643968 |
hex | 3283adb63a1d |
55541136505373 has 2 divisors, whose sum is σ = 55541136505374. Its totient is φ = 55541136505372.
The previous prime is 55541136505307. The next prime is 55541136505489. The reversal of 55541136505373 is 37350563114555.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49679420979769 + 5861715525604 = 7048363^2 + 2421098^2 .
It is a cyclic number.
It is not a de Polignac number, because 55541136505373 - 216 = 55541136439837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55541136505973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27770568252686 + 27770568252687.
It is an arithmetic number, because the mean of its divisors is an integer number (27770568252687).
Almost surely, 255541136505373 is an apocalyptic number.
It is an amenable number.
55541136505373 is a deficient number, since it is larger than the sum of its proper divisors (1).
55541136505373 is an equidigital number, since it uses as much as digits as its factorization.
55541136505373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14175000, while the sum is 53.
The spelling of 55541136505373 in words is "fifty-five trillion, five hundred forty-one billion, one hundred thirty-six million, five hundred five thousand, three hundred seventy-three".
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