Base | Representation |
---|---|
bin | 110011110010000100… |
… | …010101101001111111 |
3 | 12022111220202212111212 |
4 | 303302010111221333 |
5 | 1402332303043403 |
6 | 41313114435035 |
7 | 4005561160256 |
oct | 636204255177 |
9 | 168456685455 |
10 | 55600831103 |
11 | 21642246394 |
12 | a938732a7b |
13 | 532122857c |
14 | 299651379d |
15 | 16a64304d8 |
hex | cf2115a7f |
55600831103 has 2 divisors, whose sum is σ = 55600831104. Its totient is φ = 55600831102.
The previous prime is 55600831067. The next prime is 55600831109. The reversal of 55600831103 is 30113800655.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55600831103 - 224 = 55584053887 is a prime.
It is a super-3 number, since 3×556008311033 (a number of 33 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 55600831103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55600831109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27800415551 + 27800415552.
It is an arithmetic number, because the mean of its divisors is an integer number (27800415552).
Almost surely, 255600831103 is an apocalyptic number.
55600831103 is a deficient number, since it is larger than the sum of its proper divisors (1).
55600831103 is an equidigital number, since it uses as much as digits as its factorization.
55600831103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
The spelling of 55600831103 in words is "fifty-five billion, six hundred million, eight hundred thirty-one thousand, one hundred three".
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