Base | Representation |
---|---|
bin | 110011110010001000… |
… | …001010110110100111 |
3 | 12022111222122220012012 |
4 | 303302020022312213 |
5 | 1402333032213211 |
6 | 41313152144435 |
7 | 4005602542322 |
oct | 636210126647 |
9 | 168458586165 |
10 | 55601835431 |
11 | 21642871a0a |
12 | a938b3811b |
13 | 53214ba74c |
14 | 29966d57b9 |
15 | 16a657cd8b |
hex | cf220ada7 |
55601835431 has 2 divisors, whose sum is σ = 55601835432. Its totient is φ = 55601835430.
The previous prime is 55601835427. The next prime is 55601835491. The reversal of 55601835431 is 13453810655.
55601835431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55601835431 - 22 = 55601835427 is a prime.
It is a super-2 number, since 2×556018354312 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55601835491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27800917715 + 27800917716.
It is an arithmetic number, because the mean of its divisors is an integer number (27800917716).
Almost surely, 255601835431 is an apocalyptic number.
55601835431 is a deficient number, since it is larger than the sum of its proper divisors (1).
55601835431 is an equidigital number, since it uses as much as digits as its factorization.
55601835431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 41.
The spelling of 55601835431 in words is "fifty-five billion, six hundred one million, eight hundred thirty-five thousand, four hundred thirty-one".
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