Base | Representation |
---|---|
bin | 110011110010001000… |
… | …001010110111100011 |
3 | 12022111222122220021102 |
4 | 303302020022313203 |
5 | 1402333032213431 |
6 | 41313152145015 |
7 | 4005602542436 |
oct | 636210126743 |
9 | 168458586242 |
10 | 55601835491 |
11 | 21642871a64 |
12 | a938b3816b |
13 | 53214ba797 |
14 | 29966d581d |
15 | 16a657cdcb |
hex | cf220ade3 |
55601835491 has 2 divisors, whose sum is σ = 55601835492. Its totient is φ = 55601835490.
The previous prime is 55601835431. The next prime is 55601835493. The reversal of 55601835491 is 19453810655.
55601835491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55601835491 - 26 = 55601835427 is a prime.
It is a super-2 number, since 2×556018354912 (a number of 22 digits) contains 22 as substring.
Together with 55601835493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (55601835493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27800917745 + 27800917746.
It is an arithmetic number, because the mean of its divisors is an integer number (27800917746).
Almost surely, 255601835491 is an apocalyptic number.
55601835491 is a deficient number, since it is larger than the sum of its proper divisors (1).
55601835491 is an equidigital number, since it uses as much as digits as its factorization.
55601835491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 47.
The spelling of 55601835491 in words is "fifty-five billion, six hundred one million, eight hundred thirty-five thousand, four hundred ninety-one".
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