Base | Representation |
---|---|
bin | 110011110010010001… |
… | …101100101000111101 |
3 | 12022112011100210101002 |
4 | 303302101230220331 |
5 | 1402334202124432 |
6 | 41313321500045 |
7 | 4005633014234 |
oct | 636221545075 |
9 | 168464323332 |
10 | 55604333117 |
11 | 21644218513 |
12 | a939941625 |
13 | 5321b83578 |
14 | 2996b85b1b |
15 | 16a68c2e62 |
hex | cf246ca3d |
55604333117 has 2 divisors, whose sum is σ = 55604333118. Its totient is φ = 55604333116.
The previous prime is 55604333039. The next prime is 55604333143. The reversal of 55604333117 is 71133340655.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30788317156 + 24816015961 = 175466^2 + 157531^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55604333117 is a prime.
It is a super-2 number, since 2×556043331172 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55604335117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27802166558 + 27802166559.
It is an arithmetic number, because the mean of its divisors is an integer number (27802166559).
Almost surely, 255604333117 is an apocalyptic number.
It is an amenable number.
55604333117 is a deficient number, since it is larger than the sum of its proper divisors (1).
55604333117 is an equidigital number, since it uses as much as digits as its factorization.
55604333117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 38.
The spelling of 55604333117 in words is "fifty-five billion, six hundred four million, three hundred thirty-three thousand, one hundred seventeen".
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