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55619743 is a prime number
BaseRepresentation
bin1101010000101…
…1000010011111
310212122202221111
43110023002133
5103214312433
65304042451
71243521454
oct324130237
9125582844
1055619743
1129439a33
1216763427
13b6a52ba
14755b82b
154d39dcd
hex350b09f

55619743 has 2 divisors, whose sum is σ = 55619744. Its totient is φ = 55619742.

The previous prime is 55619741. The next prime is 55619747. The reversal of 55619743 is 34791655.

55619743 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55619743 - 21 = 55619741 is a prime.

It is a super-2 number, since 2×556197432 = 6187111622772098, which contains 22 as substring.

Together with 55619741, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 55619696 and 55619705.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55619741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27809871 + 27809872.

It is an arithmetic number, because the mean of its divisors is an integer number (27809872).

Almost surely, 255619743 is an apocalyptic number.

55619743 is a deficient number, since it is larger than the sum of its proper divisors (1).

55619743 is an equidigital number, since it uses as much as digits as its factorization.

55619743 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 113400, while the sum is 40.

The square root of 55619743 is about 7457.8645066802. The cubic root of 55619743 is about 381.7183101894.

The spelling of 55619743 in words is "fifty-five million, six hundred nineteen thousand, seven hundred forty-three".