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55656113125061 is a prime number
BaseRepresentation
bin11001010011110011100101…
…10110100011011011000101
321022001200011012212112202102
430221321302312203123011
524243332204430000221
6314212022043121445
714503010236631141
oct1451716266433305
9238050135775672
1055656113125061
11168086969a8569
1262aa63b813285
13250946c83ab07
14da5aad7c0221
15667b235c530b
hex329e72da36c5

55656113125061 has 2 divisors, whose sum is σ = 55656113125062. Its totient is φ = 55656113125060.

The previous prime is 55656113125027. The next prime is 55656113125139. The reversal of 55656113125061 is 16052131165655.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44625205644100 + 11030907480961 = 6680210^2 + 3321281^2 .

It is a cyclic number.

It is not a de Polignac number, because 55656113125061 - 222 = 55656108930757 is a prime.

It is a super-2 number, since 2×556561131250612 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 55656113124997 and 55656113125015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55656113125661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27828056562530 + 27828056562531.

It is an arithmetic number, because the mean of its divisors is an integer number (27828056562531).

Almost surely, 255656113125061 is an apocalyptic number.

It is an amenable number.

55656113125061 is a deficient number, since it is larger than the sum of its proper divisors (1).

55656113125061 is an equidigital number, since it uses as much as digits as its factorization.

55656113125061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 810000, while the sum is 47.

The spelling of 55656113125061 in words is "fifty-five trillion, six hundred fifty-six billion, one hundred thirteen million, one hundred twenty-five thousand, sixty-one".