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55661812018037 is a prime number
BaseRepresentation
bin11001010011111110001101…
…00010000110101101110101
321022002012212101100022020122
430221333012202012231311
524243430342334034122
6314214403342141325
714503301406466361
oct1451770642065565
9238065771308218
1055661812018037
1116810050869175
1262ab770281845
132509b6a40bc34
14da609060c2a1
15667d58a81142
hex329fc6886b75

55661812018037 has 2 divisors, whose sum is σ = 55661812018038. Its totient is φ = 55661812018036.

The previous prime is 55661812017883. The next prime is 55661812018097. The reversal of 55661812018037 is 73081021816655.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45176559265201 + 10485252752836 = 6721351^2 + 3238094^2 .

It is a cyclic number.

It is not a de Polignac number, because 55661812018037 - 220 = 55661810969461 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 55661812018037.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55661812018097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27830906009018 + 27830906009019.

It is an arithmetic number, because the mean of its divisors is an integer number (27830906009019).

Almost surely, 255661812018037 is an apocalyptic number.

It is an amenable number.

55661812018037 is a deficient number, since it is larger than the sum of its proper divisors (1).

55661812018037 is an equidigital number, since it uses as much as digits as its factorization.

55661812018037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2419200, while the sum is 53.

The spelling of 55661812018037 in words is "fifty-five trillion, six hundred sixty-one billion, eight hundred twelve million, eighteen thousand, thirty-seven".