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557000000143 is a prime number
BaseRepresentation
bin10000001101011111100…
…10011000001010001111
31222020201021202201211221
420012233302120022033
533111214000001033
61103514323024211
755145656611646
oct10065762301217
91866637681757
10557000000143
111a5249a85234
128bb4a20b067
13406a91c3802
141cd5d4b035d
15e74ece212d
hex81afc9828f

557000000143 has 2 divisors, whose sum is σ = 557000000144. Its totient is φ = 557000000142.

The previous prime is 557000000093. The next prime is 557000000189. The reversal of 557000000143 is 341000000755.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 557000000143 - 233 = 548410065551 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (557070000143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278500000071 + 278500000072.

It is an arithmetic number, because the mean of its divisors is an integer number (278500000072).

Almost surely, 2557000000143 is an apocalyptic number.

557000000143 is a deficient number, since it is larger than the sum of its proper divisors (1).

557000000143 is an equidigital number, since it uses as much as digits as its factorization.

557000000143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2100, while the sum is 25.

Adding to 557000000143 its reverse (341000000755), we get a palindrome (898000000898).

The spelling of 557000000143 in words is "five hundred fifty-seven billion, one hundred forty-three", and thus it is an aban number.