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557113650173 is a prime number
BaseRepresentation
bin10000001101101101000…
…11111010101111111101
31222021000012121202101022
420012312203322233331
533111432043301143
61103533502553525
755151536615103
oct10066643725775
91867005552338
10557113650173
111a52a814a183
128bb802988a5
13406c6906352
141cd70615c73
15e759c91268
hex81b68fabfd

557113650173 has 2 divisors, whose sum is σ = 557113650174. Its totient is φ = 557113650172.

The previous prime is 557113650161. The next prime is 557113650211. The reversal of 557113650173 is 371056311755.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 280813086724 + 276300563449 = 529918^2 + 525643^2 .

It is a cyclic number.

It is not a de Polignac number, because 557113650173 - 210 = 557113649149 is a prime.

It is a super-3 number, since 3×5571136501733 (a number of 36 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (557113650103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278556825086 + 278556825087.

It is an arithmetic number, because the mean of its divisors is an integer number (278556825087).

Almost surely, 2557113650173 is an apocalyptic number.

It is an amenable number.

557113650173 is a deficient number, since it is larger than the sum of its proper divisors (1).

557113650173 is an equidigital number, since it uses as much as digits as its factorization.

557113650173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 330750, while the sum is 44.

The spelling of 557113650173 in words is "five hundred fifty-seven billion, one hundred thirteen million, six hundred fifty thousand, one hundred seventy-three".