Base | Representation |
---|---|
bin | 11001010110010000011010… |
… | …11000001001000111111101 |
3 | 21022100201111001010222000120 |
4 | 30223020031120021013331 |
5 | 24301222123330001000 |
6 | 314314424522245153 |
7 | 14512050562360122 |
oct | 1453101530110775 |
9 | 238321431128016 |
10 | 55740310000125 |
11 | 16840372936a33 |
12 | 6302a190567b9 |
13 | 251439a2c614a |
14 | da9bb9aba749 |
15 | 669e002576a0 |
hex | 32b20d6091fd |
55740310000125 has 32 divisors (see below), whose sum is σ = 94136232238464. Its totient is φ = 29284461360000.
The previous prime is 55740310000117. The next prime is 55740310000129. The reversal of 55740310000125 is 52100001304755.
It is not a de Polignac number, because 55740310000125 - 23 = 55740310000117 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55740310000129) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1109234776 + ... + 1109285025.
It is an arithmetic number, because the mean of its divisors is an integer number (2941757257452).
Almost surely, 255740310000125 is an apocalyptic number.
It is an amenable number.
55740310000125 is a deficient number, since it is larger than the sum of its proper divisors (38395922238339).
55740310000125 is a wasteful number, since it uses less digits than its factorization.
55740310000125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2218519886 (or 2218519876 counting only the distinct ones).
The product of its (nonzero) digits is 21000, while the sum is 33.
The spelling of 55740310000125 in words is "fifty-five trillion, seven hundred forty billion, three hundred ten million, one hundred twenty-five", and thus it is an aban number.
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