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55740310000117 is a prime number
BaseRepresentation
bin11001010110010000011010…
…11000001001000111110101
321022100201111001010222000021
430223020031120021013311
524301222123330000432
6314314424522245141
714512050562360111
oct1453101530110765
9238321431128007
1055740310000117
1116840372936a26
126302a190567b1
13251439a2c6142
14da9bb9aba741
15669e00257697
hex32b20d6091f5

55740310000117 has 2 divisors, whose sum is σ = 55740310000118. Its totient is φ = 55740310000116.

The previous prime is 55740310000073. The next prime is 55740310000129. The reversal of 55740310000117 is 71100001304755.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55608057040561 + 132252959556 = 7457081^2 + 363666^2 .

It is a cyclic number.

It is not a de Polignac number, because 55740310000117 - 223 = 55740301611509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55740310000147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27870155000058 + 27870155000059.

It is an arithmetic number, because the mean of its divisors is an integer number (27870155000059).

Almost surely, 255740310000117 is an apocalyptic number.

It is an amenable number.

55740310000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

55740310000117 is an equidigital number, since it uses as much as digits as its factorization.

55740310000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14700, while the sum is 34.

The spelling of 55740310000117 in words is "fifty-five trillion, seven hundred forty billion, three hundred ten million, one hundred seventeen", and thus it is an aban number.