Base | Representation |
---|---|
bin | 11001010110010000011010… |
… | …11000001001000111110101 |
3 | 21022100201111001010222000021 |
4 | 30223020031120021013311 |
5 | 24301222123330000432 |
6 | 314314424522245141 |
7 | 14512050562360111 |
oct | 1453101530110765 |
9 | 238321431128007 |
10 | 55740310000117 |
11 | 16840372936a26 |
12 | 6302a190567b1 |
13 | 251439a2c6142 |
14 | da9bb9aba741 |
15 | 669e00257697 |
hex | 32b20d6091f5 |
55740310000117 has 2 divisors, whose sum is σ = 55740310000118. Its totient is φ = 55740310000116.
The previous prime is 55740310000073. The next prime is 55740310000129. The reversal of 55740310000117 is 71100001304755.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55608057040561 + 132252959556 = 7457081^2 + 363666^2 .
It is a cyclic number.
It is not a de Polignac number, because 55740310000117 - 223 = 55740301611509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55740310000147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27870155000058 + 27870155000059.
It is an arithmetic number, because the mean of its divisors is an integer number (27870155000059).
Almost surely, 255740310000117 is an apocalyptic number.
It is an amenable number.
55740310000117 is a deficient number, since it is larger than the sum of its proper divisors (1).
55740310000117 is an equidigital number, since it uses as much as digits as its factorization.
55740310000117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14700, while the sum is 34.
The spelling of 55740310000117 in words is "fifty-five trillion, seven hundred forty billion, three hundred ten million, one hundred seventeen", and thus it is an aban number.
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