Base | Representation |
---|---|
bin | 10000001111000000010… |
… | …01001111011100010111 |
3 | 1222022210211101001012012 |
4 | 20013200021033130113 |
5 | 33114344143100434 |
6 | 1104131024014435 |
7 | 55205040551003 |
oct | 10074011173427 |
9 | 1868724331165 |
10 | 557811300119 |
11 | 1a5625a33987 |
12 | 90135a6141b |
13 | 407a8301b78 |
14 | 1cdd913b703 |
15 | e79b14c3ce |
hex | 81e024f717 |
557811300119 has 2 divisors, whose sum is σ = 557811300120. Its totient is φ = 557811300118.
The previous prime is 557811300113. The next prime is 557811300121. The reversal of 557811300119 is 911003118755.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-557811300119 is a prime.
It is a super-2 number, since 2×5578113001192 (a number of 24 digits) contains 22 as substring.
Together with 557811300121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (557811300113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278905650059 + 278905650060.
It is an arithmetic number, because the mean of its divisors is an integer number (278905650060).
Almost surely, 2557811300119 is an apocalyptic number.
557811300119 is a deficient number, since it is larger than the sum of its proper divisors (1).
557811300119 is an equidigital number, since it uses as much as digits as its factorization.
557811300119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 41.
The spelling of 557811300119 in words is "five hundred fifty-seven billion, eight hundred eleven million, three hundred thousand, one hundred nineteen".
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