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557887433 is a prime number
BaseRepresentation
bin100001010000001…
…010111111001001
31102212202121200112
4201100022333021
52120304344213
6131205244105
716552651655
oct4120127711
91385677615
10557887433
11266a050a4
12136a03635
138b77260c
1454143a65
1533e9eea8
hex2140afc9

557887433 has 2 divisors, whose sum is σ = 557887434. Its totient is φ = 557887432.

The previous prime is 557887417. The next prime is 557887483. The reversal of 557887433 is 334788755.

It is a happy number.

It is an a-pointer prime, because the next prime (557887483) can be obtained adding 557887433 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 467770384 + 90117049 = 21628^2 + 9493^2 .

It is a cyclic number.

It is not a de Polignac number, because 557887433 - 24 = 557887417 is a prime.

It is a super-2 number, since 2×5578874332 = 622476775798658978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (557887403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278943716 + 278943717.

It is an arithmetic number, because the mean of its divisors is an integer number (278943717).

Almost surely, 2557887433 is an apocalyptic number.

It is an amenable number.

557887433 is a deficient number, since it is larger than the sum of its proper divisors (1).

557887433 is an equidigital number, since it uses as much as digits as its factorization.

557887433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2822400, while the sum is 50.

The square root of 557887433 is about 23619.6408313082. The cubic root of 557887433 is about 823.2192667990.

The spelling of 557887433 in words is "five hundred fifty-seven million, eight hundred eighty-seven thousand, four hundred thirty-three".