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56125443497 is a prime number
BaseRepresentation
bin110100010001010101…
…100100110110101001
312100212110220221102112
4310101111210312221
51404421103142442
641441135012105
74024561253414
oct642125446651
9170773827375
1056125443497
1121891393452
12aa6436a035
1353a5b1a2c6
142a06074b7b
1516d750b082
hexd11564da9

56125443497 has 2 divisors, whose sum is σ = 56125443498. Its totient is φ = 56125443496.

The previous prime is 56125443481. The next prime is 56125443499. The reversal of 56125443497 is 79434452165.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48920150041 + 7205293456 = 221179^2 + 84884^2 .

It is a cyclic number.

It is not a de Polignac number, because 56125443497 - 24 = 56125443481 is a prime.

Together with 56125443499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (56125443499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28062721748 + 28062721749.

It is an arithmetic number, because the mean of its divisors is an integer number (28062721749).

Almost surely, 256125443497 is an apocalyptic number.

It is an amenable number.

56125443497 is a deficient number, since it is larger than the sum of its proper divisors (1).

56125443497 is an equidigital number, since it uses as much as digits as its factorization.

56125443497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3628800, while the sum is 50.

The spelling of 56125443497 in words is "fifty-six billion, one hundred twenty-five million, four hundred forty-three thousand, four hundred ninety-seven".