Base | Representation |
---|---|
bin | 110100010001010101… |
… | …100100110110101011 |
3 | 12100212110220221102121 |
4 | 310101111210312223 |
5 | 1404421103142444 |
6 | 41441135012111 |
7 | 4024561253416 |
oct | 642125446653 |
9 | 170773827377 |
10 | 56125443499 |
11 | 21891393454 |
12 | aa6436a037 |
13 | 53a5b1a2c8 |
14 | 2a06074b7d |
15 | 16d750b084 |
hex | d11564dab |
56125443499 has 2 divisors, whose sum is σ = 56125443500. Its totient is φ = 56125443498.
The previous prime is 56125443497. The next prime is 56125443527. The reversal of 56125443499 is 99434452165.
It is a happy number.
56125443499 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56125443499 - 21 = 56125443497 is a prime.
It is a super-3 number, since 3×561254434993 (a number of 33 digits) contains 333 as substring.
Together with 56125443497, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (56125443497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28062721749 + 28062721750.
It is an arithmetic number, because the mean of its divisors is an integer number (28062721750).
Almost surely, 256125443499 is an apocalyptic number.
56125443499 is a deficient number, since it is larger than the sum of its proper divisors (1).
56125443499 is an equidigital number, since it uses as much as digits as its factorization.
56125443499 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4665600, while the sum is 52.
The spelling of 56125443499 in words is "fifty-six billion, one hundred twenty-five million, four hundred forty-three thousand, four hundred ninety-nine".
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