Base | Representation |
---|---|
bin | 101000110101101000001… |
… | …1101101000100010010001 |
3 | 201212120102102202211001122 |
4 | 1101223100131220202101 |
5 | 1213424330011431323 |
6 | 15534241121412025 |
7 | 1116335356633421 |
oct | 121532035504221 |
9 | 21776372684048 |
10 | 5612724717713 |
11 | 1874385863893 |
12 | 76794a19a015 |
13 | 31937c06b229 |
14 | 15592b9b8481 |
15 | 9aeee765ec8 |
hex | 51ad0768891 |
5612724717713 has 2 divisors, whose sum is σ = 5612724717714. Its totient is φ = 5612724717712.
The previous prime is 5612724717683. The next prime is 5612724717727. The reversal of 5612724717713 is 3177174272165.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5307830800129 + 304893917584 = 2303873^2 + 552172^2 .
It is a cyclic number.
It is not a de Polignac number, because 5612724717713 - 210 = 5612724716689 is a prime.
It is not a weakly prime, because it can be changed into another prime (5612724710713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2806362358856 + 2806362358857.
It is an arithmetic number, because the mean of its divisors is an integer number (2806362358857).
Almost surely, 25612724717713 is an apocalyptic number.
It is an amenable number.
5612724717713 is a deficient number, since it is larger than the sum of its proper divisors (1).
5612724717713 is an equidigital number, since it uses as much as digits as its factorization.
5612724717713 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3457440, while the sum is 53.
Adding to 5612724717713 its reverse (3177174272165), we get a palindrome (8789898989878).
The spelling of 5612724717713 in words is "five trillion, six hundred twelve billion, seven hundred twenty-four million, seven hundred seventeen thousand, seven hundred thirteen".
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