Base | Representation |
---|---|
bin | 101000110111011111100… |
… | …0110001111000101110111 |
3 | 201212221202110021211201101 |
4 | 1101232333012033011313 |
5 | 1214011024423320212 |
6 | 15540142301110531 |
7 | 1116536523101215 |
oct | 121567706170567 |
9 | 21787673254641 |
10 | 5616728338807 |
11 | 187604a7a0653 |
12 | 768686b58447 |
13 | 319869659bb1 |
14 | 155bcb5d1cb5 |
15 | 9b185ea4157 |
hex | 51bbf18f177 |
5616728338807 has 2 divisors, whose sum is σ = 5616728338808. Its totient is φ = 5616728338806.
The previous prime is 5616728338763. The next prime is 5616728338913. The reversal of 5616728338807 is 7088338276165.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5616728338807 - 215 = 5616728306039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5616728332807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2808364169403 + 2808364169404.
It is an arithmetic number, because the mean of its divisors is an integer number (2808364169404).
Almost surely, 25616728338807 is an apocalyptic number.
5616728338807 is a deficient number, since it is larger than the sum of its proper divisors (1).
5616728338807 is an equidigital number, since it uses as much as digits as its factorization.
5616728338807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81285120, while the sum is 64.
The spelling of 5616728338807 in words is "five trillion, six hundred sixteen billion, seven hundred twenty-eight million, three hundred thirty-eight thousand, eight hundred seven".
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