Base | Representation |
---|---|
bin | 10000010110010111011… |
… | …01001011000011011011 |
3 | 1222201000020212202010122 |
4 | 20023023231023003123 |
5 | 33200442410140313 |
6 | 1110023122303455 |
7 | 55405006550204 |
oct | 10131355130333 |
9 | 1881006782118 |
10 | 561763365083 |
11 | 1a7273857878 |
12 | 90a594b7b8b |
13 | 40c8800c04b |
14 | 1d291d745ab |
15 | e92d0a4708 |
hex | 82cbb4b0db |
561763365083 has 2 divisors, whose sum is σ = 561763365084. Its totient is φ = 561763365082.
The previous prime is 561763365077. The next prime is 561763365143. The reversal of 561763365083 is 380563367165.
561763365083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 561763365083 - 26 = 561763365019 is a prime.
It is not a weakly prime, because it can be changed into another prime (561763361083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280881682541 + 280881682542.
It is an arithmetic number, because the mean of its divisors is an integer number (280881682542).
Almost surely, 2561763365083 is an apocalyptic number.
561763365083 is a deficient number, since it is larger than the sum of its proper divisors (1).
561763365083 is an equidigital number, since it uses as much as digits as its factorization.
561763365083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8164800, while the sum is 53.
The spelling of 561763365083 in words is "five hundred sixty-one billion, seven hundred sixty-three million, three hundred sixty-five thousand, eighty-three".
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