Base | Representation |
---|---|
bin | 10000010110010111011… |
… | …01001011000100010111 |
3 | 1222201000020212202012212 |
4 | 20023023231023010113 |
5 | 33200442410141033 |
6 | 1110023122304035 |
7 | 55405006550321 |
oct | 10131355130427 |
9 | 1881006782185 |
10 | 561763365143 |
11 | 1a7273857922 |
12 | 90a594b801b |
13 | 40c8800c096 |
14 | 1d291d74611 |
15 | e92d0a4748 |
hex | 82cbb4b117 |
561763365143 has 2 divisors, whose sum is σ = 561763365144. Its totient is φ = 561763365142.
The previous prime is 561763365083. The next prime is 561763365199. The reversal of 561763365143 is 341563367165.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 561763365143 - 210 = 561763364119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 561763365091 and 561763365100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (561763365343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280881682571 + 280881682572.
It is an arithmetic number, because the mean of its divisors is an integer number (280881682572).
Almost surely, 2561763365143 is an apocalyptic number.
561763365143 is a deficient number, since it is larger than the sum of its proper divisors (1).
561763365143 is an equidigital number, since it uses as much as digits as its factorization.
561763365143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4082400, while the sum is 50.
The spelling of 561763365143 in words is "five hundred sixty-one billion, seven hundred sixty-three million, three hundred sixty-five thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •