Base | Representation |
---|---|
bin | 1000000000011010011000101… |
… | …1011100111101000101011010 |
3 | 2201212211211022012202012202020 |
4 | 2000012212023130331011122 |
5 | 1042321244341220020100 |
6 | 5314131515303515310 |
7 | 226446354054120642 |
oct | 20006461334750532 |
9 | 2655754265665666 |
10 | 563403264610650 |
11 | 153576a89a86282 |
12 | 532333b1458b36 |
13 | 1b24a913851689 |
14 | 9d1ac13655522 |
15 | 452062a0005a0 |
hex | 200698b73d15a |
563403264610650 has 48 divisors (see below), whose sum is σ = 1400888242842624. Its totient is φ = 149848596734080.
The previous prime is 563403264610609. The next prime is 563403264610673. The reversal of 563403264610650 is 56016462304365.
It is a junction number, because it is equal to n+sod(n) for n = 563403264610593 and 563403264610602.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4903365219 + ... + 4903480118.
It is an arithmetic number, because the mean of its divisors is an integer number (29185171725888).
Almost surely, 2563403264610650 is an apocalyptic number.
563403264610650 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
563403264610650 is an abundant number, since it is smaller than the sum of its proper divisors (837484978231974).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
563403264610650 is a wasteful number, since it uses less digits than its factorization.
563403264610650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9806845735 (or 9806845730 counting only the distinct ones).
The product of its (nonzero) digits is 9331200, while the sum is 51.
The spelling of 563403264610650 in words is "five hundred sixty-three trillion, four hundred three billion, two hundred sixty-four million, six hundred ten thousand, six hundred fifty".
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