Base | Representation |
---|---|
bin | 101001000100011000110… |
… | …1101011001101011001101 |
3 | 201222121020101221101222111 |
4 | 1102020301231121223031 |
5 | 1214434233234342143 |
6 | 20001002231144021 |
7 | 1121540004662236 |
oct | 122106155315315 |
9 | 21877211841874 |
10 | 5644421012173 |
11 | 1886870569a69 |
12 | 771b15215011 |
13 | 31c3609b3058 |
14 | 15729742208d |
15 | 9bc5726099d |
hex | 52231b59acd |
5644421012173 has 2 divisors, whose sum is σ = 5644421012174. Its totient is φ = 5644421012172.
The previous prime is 5644421012171. The next prime is 5644421012203. The reversal of 5644421012173 is 3712101244465.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4541578685604 + 1102842326569 = 2131098^2 + 1050163^2 .
It is a cyclic number.
It is not a de Polignac number, because 5644421012173 - 21 = 5644421012171 is a prime.
Together with 5644421012171, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5644421012171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2822210506086 + 2822210506087.
It is an arithmetic number, because the mean of its divisors is an integer number (2822210506087).
Almost surely, 25644421012173 is an apocalyptic number.
It is an amenable number.
5644421012173 is a deficient number, since it is larger than the sum of its proper divisors (1).
5644421012173 is an equidigital number, since it uses as much as digits as its factorization.
5644421012173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 40.
The spelling of 5644421012173 in words is "five trillion, six hundred forty-four billion, four hundred twenty-one million, twelve thousand, one hundred seventy-three".
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