Base | Representation |
---|---|
bin | 11001101011000000101100… |
… | …11111001001111000001111 |
3 | 21101212220011102100112110212 |
4 | 30311200112133021320033 |
5 | 24344413104403414203 |
6 | 320022202503153035 |
7 | 14614424362321406 |
oct | 1465402637117017 |
9 | 241786142315425 |
10 | 56453427404303 |
11 | 16a95845039526 |
12 | 63b907674577b |
13 | 25666c62602b7 |
14 | dd250918c63d |
15 | 67d73ac031d8 |
hex | 3358167c9e0f |
56453427404303 has 2 divisors, whose sum is σ = 56453427404304. Its totient is φ = 56453427404302.
The previous prime is 56453427404273. The next prime is 56453427404371. The reversal of 56453427404303 is 30340472435465.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56453427404303 - 28 = 56453427404047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56453427404603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28226713702151 + 28226713702152.
It is an arithmetic number, because the mean of its divisors is an integer number (28226713702152).
Almost surely, 256453427404303 is an apocalyptic number.
56453427404303 is a deficient number, since it is larger than the sum of its proper divisors (1).
56453427404303 is an equidigital number, since it uses as much as digits as its factorization.
56453427404303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14515200, while the sum is 50.
Adding to 56453427404303 its reverse (30340472435465), we get a palindrome (86793899839768).
The spelling of 56453427404303 in words is "fifty-six trillion, four hundred fifty-three billion, four hundred twenty-seven million, four hundred four thousand, three hundred three".
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