Base | Representation |
---|---|
bin | 110100100111011111… |
… | …101000111001011101 |
3 | 12101211101102010101112 |
4 | 310213133220321131 |
5 | 1411201234232003 |
6 | 41542054351405 |
7 | 4040024052143 |
oct | 644737507135 |
9 | 171741363345 |
10 | 56497180253 |
11 | 21a62204808 |
12 | ab4895b565 |
13 | 5434b44297 |
14 | 2a3d59d593 |
15 | 1709e8a3d8 |
hex | d277e8e5d |
56497180253 has 2 divisors, whose sum is σ = 56497180254. Its totient is φ = 56497180252.
The previous prime is 56497180247. The next prime is 56497180283. The reversal of 56497180253 is 35208179465.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50051980729 + 6445199524 = 223723^2 + 80282^2 .
It is a cyclic number.
It is not a de Polignac number, because 56497180253 - 210 = 56497179229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56497180213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28248590126 + 28248590127.
It is an arithmetic number, because the mean of its divisors is an integer number (28248590127).
It is a 1-persistent number, because it is pandigital, but 2⋅56497180253 = 112994360506 is not.
Almost surely, 256497180253 is an apocalyptic number.
It is an amenable number.
56497180253 is a deficient number, since it is larger than the sum of its proper divisors (1).
56497180253 is an equidigital number, since it uses as much as digits as its factorization.
56497180253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 50.
The spelling of 56497180253 in words is "fifty-six billion, four hundred ninety-seven million, one hundred eighty thousand, two hundred fifty-three".
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