Base | Representation |
---|---|
bin | 110100101011010101… |
… | …111011011101111101 |
3 | 12101222212220021211211 |
4 | 310223111323131331 |
5 | 1411314301244431 |
6 | 41552322244421 |
7 | 4041436613656 |
oct | 645325733575 |
9 | 171885807754 |
10 | 56561743741 |
11 | 21a956a2268 |
12 | ab664b6711 |
13 | 544532b429 |
14 | 2a47da852d |
15 | 17109902b1 |
hex | d2b57b77d |
56561743741 has 2 divisors, whose sum is σ = 56561743742. Its totient is φ = 56561743740.
The previous prime is 56561743717. The next prime is 56561743787. The reversal of 56561743741 is 14734716565.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29325192516 + 27236551225 = 171246^2 + 165035^2 .
It is a cyclic number.
It is not a de Polignac number, because 56561743741 - 25 = 56561743709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56561747741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28280871870 + 28280871871.
It is an arithmetic number, because the mean of its divisors is an integer number (28280871871).
Almost surely, 256561743741 is an apocalyptic number.
It is an amenable number.
56561743741 is a deficient number, since it is larger than the sum of its proper divisors (1).
56561743741 is an equidigital number, since it uses as much as digits as its factorization.
56561743741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2116800, while the sum is 49.
The spelling of 56561743741 in words is "fifty-six billion, five hundred sixty-one million, seven hundred forty-three thousand, seven hundred forty-one".
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