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56711120237 is a prime number
BaseRepresentation
bin110100110100001111…
…110000010101101101
312102101021222101212122
4310310033300111231
51412121021321422
642015220042325
74045232365652
oct646417602555
9172337871778
1056711120237
1122061a49012
12aba85333a5
13546a26c5a5
142a5db6dc29
15171db49d42
hexd343f056d

56711120237 has 2 divisors, whose sum is σ = 56711120238. Its totient is φ = 56711120236.

The previous prime is 56711120231. The next prime is 56711120243. The reversal of 56711120237 is 73202111765.

It is a balanced prime because it is at equal distance from previous prime (56711120231) and next prime (56711120243).

It can be written as a sum of positive squares in only one way, i.e., 46261987396 + 10449132841 = 215086^2 + 102221^2 .

It is a cyclic number.

It is not a de Polignac number, because 56711120237 - 214 = 56711103853 is a prime.

It is a super-3 number, since 3×567111202373 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 56711120197 and 56711120206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56711120231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28355560118 + 28355560119.

It is an arithmetic number, because the mean of its divisors is an integer number (28355560119).

Almost surely, 256711120237 is an apocalyptic number.

It is an amenable number.

56711120237 is a deficient number, since it is larger than the sum of its proper divisors (1).

56711120237 is an equidigital number, since it uses as much as digits as its factorization.

56711120237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17640, while the sum is 35.

The spelling of 56711120237 in words is "fifty-six billion, seven hundred eleven million, one hundred twenty thousand, two hundred thirty-seven".