Base | Representation |
---|---|
bin | 110100110100010000… |
… | …110101101010110101 |
3 | 12102101022111211102021 |
4 | 310310100311222311 |
5 | 1412121104413323 |
6 | 42015230113141 |
7 | 4045234660612 |
oct | 646420655265 |
9 | 172338454367 |
10 | 56711404213 |
11 | 22062122402 |
12 | aba864b7b1 |
13 | 546a33b919 |
14 | 2a5dc05509 |
15 | 171dba405d |
hex | d34435ab5 |
56711404213 has 2 divisors, whose sum is σ = 56711404214. Its totient is φ = 56711404212.
The previous prime is 56711404177. The next prime is 56711404241. The reversal of 56711404213 is 31240411765.
56711404213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45559621809 + 11151782404 = 213447^2 + 105602^2 .
It is a cyclic number.
It is not a de Polignac number, because 56711404213 - 217 = 56711273141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56711407213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28355702106 + 28355702107.
It is an arithmetic number, because the mean of its divisors is an integer number (28355702107).
Almost surely, 256711404213 is an apocalyptic number.
It is an amenable number.
56711404213 is a deficient number, since it is larger than the sum of its proper divisors (1).
56711404213 is an equidigital number, since it uses as much as digits as its factorization.
56711404213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 56711404213 its reverse (31240411765), we get a palindrome (87951815978).
The spelling of 56711404213 in words is "fifty-six billion, seven hundred eleven million, four hundred four thousand, two hundred thirteen".
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