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568104401897 is a prime number
BaseRepresentation
bin10000100010001011010…
…10010011101111101001
32000022101011122210100222
420101011222103233221
533301434211330042
61112552240535425
756021104512044
oct10210552235751
92008334583328
10568104401897
111a9a2814066a
1292129021575
1341758943336
141d6d4199c5b
15eb9eb052d2
hex8445a93be9

568104401897 has 2 divisors, whose sum is σ = 568104401898. Its totient is φ = 568104401896.

The previous prime is 568104401849. The next prime is 568104401899. The reversal of 568104401897 is 798104401865.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 399147231961 + 168957169936 = 631781^2 + 411044^2 .

It is a cyclic number.

It is not a de Polignac number, because 568104401897 - 222 = 568100207593 is a prime.

It is a super-2 number, since 2×5681044018972 (a number of 24 digits) contains 22 as substring.

Together with 568104401899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (568104401899) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 284052200948 + 284052200949.

It is an arithmetic number, because the mean of its divisors is an integer number (284052200949).

Almost surely, 2568104401897 is an apocalyptic number.

It is an amenable number.

568104401897 is a deficient number, since it is larger than the sum of its proper divisors (1).

568104401897 is an equidigital number, since it uses as much as digits as its factorization.

568104401897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1935360, while the sum is 53.

The spelling of 568104401897 in words is "five hundred sixty-eight billion, one hundred four million, four hundred one thousand, eight hundred ninety-seven".