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57001352764373 is a prime number
BaseRepresentation
bin11001111010111101010010…
…11000100001101111010101
321110211021110021120210101022
430331132221120201233111
524432402232301424443
6321122020541210525
715002132442121643
oct1475365130415725
9243737407523338
1057001352764373
1117187157682316
1264872b1860a45
1325a628739bca4
141010c47378193
1568cb08ec2e68
hex33d7a9621bd5

57001352764373 has 2 divisors, whose sum is σ = 57001352764374. Its totient is φ = 57001352764372.

The previous prime is 57001352764273. The next prime is 57001352764409. The reversal of 57001352764373 is 37346725310075.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28599200143684 + 28402152620689 = 5347822^2 + 5329367^2 .

It is a cyclic number.

It is not a de Polignac number, because 57001352764373 - 28 = 57001352764117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57001352764273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28500676382186 + 28500676382187.

It is an arithmetic number, because the mean of its divisors is an integer number (28500676382187).

Almost surely, 257001352764373 is an apocalyptic number.

It is an amenable number.

57001352764373 is a deficient number, since it is larger than the sum of its proper divisors (1).

57001352764373 is an equidigital number, since it uses as much as digits as its factorization.

57001352764373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11113200, while the sum is 53.

The spelling of 57001352764373 in words is "fifty-seven trillion, one billion, three hundred fifty-two million, seven hundred sixty-four thousand, three hundred seventy-three".