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5725111838741 is a prime number
BaseRepresentation
bin101001101001111101101…
…0000011110100000010101
3202021022111212222002212122
41103103323100132200111
51222300012112314431
620102025143425325
71130424415460411
oct123237320364025
922238455862778
105725111838741
11190800841a299
12785694455245
13326b4cc94989
1415b14dc27d41
159ddcb1dda7b
hex534fb41e815

5725111838741 has 2 divisors, whose sum is σ = 5725111838742. Its totient is φ = 5725111838740.

The previous prime is 5725111838711. The next prime is 5725111838749. The reversal of 5725111838741 is 1478381115275.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4583945230225 + 1141166608516 = 2141015^2 + 1068254^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5725111838741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5725111838749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2862555919370 + 2862555919371.

It is an arithmetic number, because the mean of its divisors is an integer number (2862555919371).

Almost surely, 25725111838741 is an apocalyptic number.

It is an amenable number.

5725111838741 is a deficient number, since it is larger than the sum of its proper divisors (1).

5725111838741 is an equidigital number, since it uses as much as digits as its factorization.

5725111838741 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1881600, while the sum is 53.

The spelling of 5725111838741 in words is "five trillion, seven hundred twenty-five billion, one hundred eleven million, eight hundred thirty-eight thousand, seven hundred forty-one".