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57419413 is a prime number
BaseRepresentation
bin1101101100001…
…0011010010101
311000001012121221
43123002122111
5104144410123
65410410341
71265025352
oct333023225
9130035557
1057419413
112a459067
12172909b1
13bb854ac
1478a9629
15509325d
hex36c2695

57419413 has 2 divisors, whose sum is σ = 57419414. Its totient is φ = 57419412.

The previous prime is 57419399. The next prime is 57419429. The reversal of 57419413 is 31491475.

57419413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56205009 + 1214404 = 7497^2 + 1102^2 .

It is a cyclic number.

It is not a de Polignac number, because 57419413 - 25 = 57419381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57410413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28709706 + 28709707.

It is an arithmetic number, because the mean of its divisors is an integer number (28709707).

Almost surely, 257419413 is an apocalyptic number.

It is an amenable number.

57419413 is a deficient number, since it is larger than the sum of its proper divisors (1).

57419413 is an equidigital number, since it uses as much as digits as its factorization.

57419413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 34.

The square root of 57419413 is about 7577.5598315025. The cubic root of 57419413 is about 385.7917321723.

The spelling of 57419413 in words is "fifty-seven million, four hundred nineteen thousand, four hundred thirteen".