Search a number
-
+
57543711150071 is a prime number
BaseRepresentation
bin11010001010101111100000…
…11101100100111111110111
321112202010101011120110002202
431011113300131210333313
530020244010023300241
6322215114351455115
715056252543255216
oct1505276035447767
9245663334513082
1057543711150071
1117376172867943
12655443452749b
13261546c0776c3
14102d1b807507d
1569bc9d693d9b
hex3455f0764ff7

57543711150071 has 2 divisors, whose sum is σ = 57543711150072. Its totient is φ = 57543711150070.

The previous prime is 57543711149993. The next prime is 57543711150179. The reversal of 57543711150071 is 17005111734575.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-57543711150071 is a prime.

It is a super-2 number, since 2×575437111500712 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 57543711149998 and 57543711150025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57543711150671) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28771855575035 + 28771855575036.

It is an arithmetic number, because the mean of its divisors is an integer number (28771855575036).

Almost surely, 257543711150071 is an apocalyptic number.

57543711150071 is a deficient number, since it is larger than the sum of its proper divisors (1).

57543711150071 is an equidigital number, since it uses as much as digits as its factorization.

57543711150071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 514500, while the sum is 47.

The spelling of 57543711150071 in words is "fifty-seven trillion, five hundred forty-three billion, seven hundred eleven million, one hundred fifty thousand, seventy-one".