Base | Representation |
---|---|
bin | 101001111110001010010… |
… | …0101011000010111110001 |
3 | 202102110110201220020100022 |
4 | 1103330110211120113301 |
5 | 1224002330011001001 |
6 | 20134001151333225 |
7 | 1133521320366362 |
oct | 123742445302761 |
9 | 22373421806308 |
10 | 5768486422001 |
11 | 1924446223716 |
12 | 791b7a521215 |
13 | 32ac73211264 |
14 | 15d2a6667b69 |
15 | a00b90ac11b |
hex | 53f149585f1 |
5768486422001 has 2 divisors, whose sum is σ = 5768486422002. Its totient is φ = 5768486422000.
The previous prime is 5768486421967. The next prime is 5768486422003. The reversal of 5768486422001 is 1002246848675.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5105362845025 + 663123576976 = 2259505^2 + 814324^2 .
It is a cyclic number.
It is not a de Polignac number, because 5768486422001 - 218 = 5768486159857 is a prime.
Together with 5768486422003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5768486422003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2884243211000 + 2884243211001.
It is an arithmetic number, because the mean of its divisors is an integer number (2884243211001).
Almost surely, 25768486422001 is an apocalyptic number.
It is an amenable number.
5768486422001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5768486422001 is an equidigital number, since it uses as much as digits as its factorization.
5768486422001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5160960, while the sum is 53.
The spelling of 5768486422001 in words is "five trillion, seven hundred sixty-eight billion, four hundred eighty-six million, four hundred twenty-two thousand, one".
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