Search a number
-
+
58803260955581 is a prime number
BaseRepresentation
bin11010101111011001100110…
…11110110001101110111101
321201012112111100202010002102
431113230303132301232331
530201413034301034311
6325021502315234445
715246252424046462
oct1527546336615675
9251175440663072
1058803260955581
11178113608a222a
126718571148a25
1326a717ba551cc
141074143343669
156be91b30643b
hex357b337b1bbd

58803260955581 has 2 divisors, whose sum is σ = 58803260955582. Its totient is φ = 58803260955580.

The previous prime is 58803260955539. The next prime is 58803260955583. The reversal of 58803260955581 is 18555906230885.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53915845393081 + 4887415562500 = 7342741^2 + 2210750^2 .

It is a cyclic number.

It is not a de Polignac number, because 58803260955581 - 238 = 58528383048637 is a prime.

It is a super-2 number, since 2×588032609555812 (a number of 28 digits) contains 22 as substring.

Together with 58803260955583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (58803260955583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29401630477790 + 29401630477791.

It is an arithmetic number, because the mean of its divisors is an integer number (29401630477791).

Almost surely, 258803260955581 is an apocalyptic number.

It is an amenable number.

58803260955581 is a deficient number, since it is larger than the sum of its proper divisors (1).

58803260955581 is an equidigital number, since it uses as much as digits as its factorization.

58803260955581 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680000, while the sum is 65.

The spelling of 58803260955581 in words is "fifty-eight trillion, eight hundred three billion, two hundred sixty million, nine hundred fifty-five thousand, five hundred eighty-one".