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594052094021 is a prime number
BaseRepresentation
bin10001010010100000100…
…00111001100001000101
32002210100111211010101012
420221100100321201011
534213104314002041
61132523114012005
760630110325161
oct10512020714105
92083314733335
10594052094021
11209a32a13821
129716aa17005
1344032601009
1420a76355ca1
15106bcac53eb
hex8a50439845

594052094021 has 2 divisors, whose sum is σ = 594052094022. Its totient is φ = 594052094020.

The previous prime is 594052093933. The next prime is 594052094023. The reversal of 594052094021 is 120490250495.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 550325101921 + 43726992100 = 741839^2 + 209110^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-594052094021 is a prime.

Together with 594052094023, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 594052094021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (594052094023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 297026047010 + 297026047011.

It is an arithmetic number, because the mean of its divisors is an integer number (297026047011).

Almost surely, 2594052094021 is an apocalyptic number.

It is an amenable number.

594052094021 is a deficient number, since it is larger than the sum of its proper divisors (1).

594052094021 is an equidigital number, since it uses as much as digits as its factorization.

594052094021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 594052094021 in words is "five hundred ninety-four billion, fifty-two million, ninety-four thousand, twenty-one".