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594434434493 is a prime number
BaseRepresentation
bin10001010011001110000…
…11011010010110111101
32002211100011021000220102
420221213003122112331
534214400203400433
61133025052530445
760642432216344
oct10514703322675
92084304230812
10594434434493
1120a109817889
1297256a80a25
134409389b593
1420ab1040b5b
15106e144b4e8
hex8a670da5bd

594434434493 has 2 divisors, whose sum is σ = 594434434494. Its totient is φ = 594434434492.

The previous prime is 594434434439. The next prime is 594434434543. The reversal of 594434434493 is 394434434495.

It is a happy number.

Together with previous prime (594434434439) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 572446586404 + 21987848089 = 756602^2 + 148283^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-594434434493 is a prime.

It is a super-2 number, since 2×5944344344932 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (594434433493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 297217217246 + 297217217247.

It is an arithmetic number, because the mean of its divisors is an integer number (297217217247).

Almost surely, 2594434434493 is an apocalyptic number.

It is an amenable number.

594434434493 is a deficient number, since it is larger than the sum of its proper divisors (1).

594434434493 is an equidigital number, since it uses as much as digits as its factorization.

594434434493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 44789760, while the sum is 56.

The spelling of 594434434493 in words is "five hundred ninety-four billion, four hundred thirty-four million, four hundred thirty-four thousand, four hundred ninety-three".