Base | Representation |
---|---|
bin | 1011001010010110… |
… | …01000100111100101 |
3 | 120110121201200212002 |
4 | 11211023020213211 |
5 | 44233022304442 |
6 | 2430341335045 |
7 | 301332301124 |
oct | 54513104745 |
9 | 16417650762 |
10 | 5992384997 |
11 | 25a55aa5a5 |
12 | 11b2a07485 |
13 | 746630951 |
14 | 40bbc9abb |
15 | 251131732 |
hex | 1652c89e5 |
5992384997 has 2 divisors, whose sum is σ = 5992384998. Its totient is φ = 5992384996.
The previous prime is 5992384967. The next prime is 5992384999. The reversal of 5992384997 is 7994832995.
5992384997 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4225780036 + 1766604961 = 65006^2 + 42031^2 .
It is a cyclic number.
It is not a de Polignac number, because 5992384997 - 26 = 5992384933 is a prime.
Together with 5992384999, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5992384999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2996192498 + 2996192499.
It is an arithmetic number, because the mean of its divisors is an integer number (2996192499).
Almost surely, 25992384997 is an apocalyptic number.
It is an amenable number.
5992384997 is a deficient number, since it is larger than the sum of its proper divisors (1).
5992384997 is an equidigital number, since it uses as much as digits as its factorization.
5992384997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 44089920, while the sum is 65.
The square root of 5992384997 is about 77410.4966848812. The cubic root of 5992384997 is about 1816.3515241166.
The spelling of 5992384997 in words is "five billion, nine hundred ninety-two million, three hundred eighty-four thousand, nine hundred ninety-seven".
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