Base | Representation |
---|---|
bin | 11011010110000000111001… |
… | …01010110000001001011111 |
3 | 21212220101002200211001002121 |
4 | 31223000130222300021133 |
5 | 30340132241404111221 |
6 | 331515203513003411 |
7 | 15444152012236504 |
oct | 1553003452601137 |
9 | 255811080731077 |
10 | 60130023113311 |
11 | 18182aaa508648 |
12 | 68b17270b3567 |
13 | 2772310486528 |
14 | 10bc446cdb4ab |
15 | 6e41be97ea41 |
hex | 36b01cab025f |
60130023113311 has 4 divisors (see below), whose sum is σ = 61264551851352. Its totient is φ = 58995494375272.
The previous prime is 60130023113309. The next prime is 60130023113327. The reversal of 60130023113311 is 11331132003106.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 60130023113311 - 21 = 60130023113309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (60130023113341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 567264368941 + ... + 567264369046.
It is an arithmetic number, because the mean of its divisors is an integer number (15316137962838).
Almost surely, 260130023113311 is an apocalyptic number.
60130023113311 is a deficient number, since it is larger than the sum of its proper divisors (1134528738041).
60130023113311 is a wasteful number, since it uses less digits than its factorization.
60130023113311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1134528738040.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 60130023113311 its reverse (11331132003106), we get a palindrome (71461155116417).
The spelling of 60130023113311 in words is "sixty trillion, one hundred thirty billion, twenty-three million, one hundred thirteen thousand, three hundred eleven".
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