6013310497 has 2 divisors, whose sum is σ = 6013310498. Its totient is φ = 6013310496.

The previous prime is 6013310461. The next prime is 6013310531. The reversal of 6013310497 is 7940133106.

6013310497 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (6013310531) can be obtained adding 6013310497 to its sum of digits (34).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5040432016 + 972878481 = 70996^2 + 31191^2 .

It is a cyclic number.

It is not a de Polignac number, because 6013310497 - 2¹¹ = 6013308449 is a prime.

It is not a weakly prime, because it can be changed into another prime (6013313497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3006655248 + 3006655249.

It is an arithmetic number, because the mean of its divisors is an integer number (3006655249).

Almost surely, 2^6013310497 is an apocalyptic number.

It is an amenable number.

6013310497 is a deficient number, since it is larger than the sum of its proper divisors (1).

6013310497 is an equidigital number, since it uses as much as digits as its factorization.

6013310497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 34.

The square root of 6013310497 is about 77545.5382146517. The cubic root of 6013310497 is about 1818.4633103190.

The spelling of 6013310497 in words is "six billion, thirteen million, three hundred ten thousand, four hundred ninety-seven".