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602240642731907 is a prime number
BaseRepresentation
bin1000100011101111000001001…
…1100101000100111110000011
32220222100122100212111102002122
42020323300103211010332003
51112414102314014410112
65532505310514234455
7240565310356236044
oct21073602345047603
92828318325442078
10602240642731907
1116498a905493a63
1257666330885a2b
131cb0708365044a
14a8a08618b88cb
1549959db765872
hex223bc13944f83

602240642731907 has 2 divisors, whose sum is σ = 602240642731908. Its totient is φ = 602240642731906.

The previous prime is 602240642731901. The next prime is 602240642731909. The reversal of 602240642731907 is 709137246042206.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 602240642731907 - 230 = 602239568990083 is a prime.

Together with 602240642731909, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (602240642731901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 301120321365953 + 301120321365954.

It is an arithmetic number, because the mean of its divisors is an integer number (301120321365954).

Almost surely, 2602240642731907 is an apocalyptic number.

602240642731907 is a deficient number, since it is larger than the sum of its proper divisors (1).

602240642731907 is an equidigital number, since it uses as much as digits as its factorization.

602240642731907 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6096384, while the sum is 53.

The spelling of 602240642731907 in words is "six hundred two trillion, two hundred forty billion, six hundred forty-two million, seven hundred thirty-one thousand, nine hundred seven".