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60231230002409 is a prime number
BaseRepresentation
bin11011011000111101011010…
…00100011001010011101001
321220021001022222102200221112
431230132231010121103221
530343312024340034114
6332033502311520105
715454364012505224
oct1554365504312351
9256231288380845
1060231230002409
1118211a15125354
126909271089035
13277ba1c03001b
1410c32c83625bb
156e6b44b1613e
hex36c7ad1194e9

60231230002409 has 2 divisors, whose sum is σ = 60231230002410. Its totient is φ = 60231230002408.

The previous prime is 60231230002399. The next prime is 60231230002441. The reversal of 60231230002409 is 90420003213206.

It is an a-pointer prime, because the next prime (60231230002441) can be obtained adding 60231230002409 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37761762403600 + 22469467598809 = 6145060^2 + 4740197^2 .

It is a cyclic number.

It is not a de Polignac number, because 60231230002409 - 240 = 59131718374633 is a prime.

It is a super-2 number, since 2×602312300024092 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (60231230002609) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30115615001204 + 30115615001205.

It is an arithmetic number, because the mean of its divisors is an integer number (30115615001205).

Almost surely, 260231230002409 is an apocalyptic number.

It is an amenable number.

60231230002409 is a deficient number, since it is larger than the sum of its proper divisors (1).

60231230002409 is an equidigital number, since it uses as much as digits as its factorization.

60231230002409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 60231230002409 in words is "sixty trillion, two hundred thirty-one billion, two hundred thirty million, two thousand, four hundred nine".