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6041551145011 is a prime number
BaseRepresentation
bin101011111101010100010…
…0000101000100000110011
3210101120022002100102022221
41113322220200220200303
51242441044043120021
620503241132141511
71162326161263504
oct127725040504063
923346262312287
106041551145011
111a1a231133718
12816a87307897
1334a93c8a0c35
1416c5ac3b4bab
15a724bc1d241
hex57ea8828833

6041551145011 has 2 divisors, whose sum is σ = 6041551145012. Its totient is φ = 6041551145010.

The previous prime is 6041551145009. The next prime is 6041551145027. The reversal of 6041551145011 is 1105411551406.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 6041551145011 - 21 = 6041551145009 is a prime.

Together with 6041551145009, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (6041551145611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3020775572505 + 3020775572506.

It is an arithmetic number, because the mean of its divisors is an integer number (3020775572506).

Almost surely, 26041551145011 is an apocalyptic number.

6041551145011 is a deficient number, since it is larger than the sum of its proper divisors (1).

6041551145011 is an equidigital number, since it uses as much as digits as its factorization.

6041551145011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 34.

Adding to 6041551145011 its reverse (1105411551406), we get a palindrome (7146962696417).

The spelling of 6041551145011 in words is "six trillion, forty-one billion, five hundred fifty-one million, one hundred forty-five thousand, eleven".